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Topic: A Riddle |
Paul Graupp
From:
Macon Ga USA
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Posted 9 Aug 2002 10:28 am |
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In standard, seven sector displays, what do the digits 4, 5 and 6 have; that the digits
1, 2 & 3 and 7, 8 & 9 do not ??
Regards, Paul  |
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Bill Terry
From:
Bastrop, TX
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Posted 9 Aug 2002 11:04 am
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The same number of segments lit as the number represented?
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Paul Graupp
From:
Macon Ga USA
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Posted 9 Aug 2002 4:16 pm
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That's right Bill !! I have never heard this mentioned anywhere and it just struck me one day. I was wondering if anyone else had noticed the coincidence. Good thinking there and keen perception as well ! How long have you known this ??
Regards, Paul   |
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Donny Hinson
From:
Glen Burnie, Md. U.S.A.
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Posted 9 Aug 2002 5:08 pm
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That's a good one, Paul! Here's another...
Remember the year 1961? Plug that into your calculator. Now if you rotate the calculator 180 degrees...it still reads 1961.
How soon (what year) will that "curiosity" happen again? |
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Paul Graupp
From:
Macon Ga USA
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Posted 9 Aug 2002 5:40 pm
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Donny; I couldn't begin to draw this so I'll have to trust my writing skills....
Three resistors in a straight line, R-1, R-2 and R-3 in series between points A and B. All are 300 ohms. Over the resistors, there is a jumper between point A and the junction of R-2 and R-3 which appears to short out R-1 & R-2. Below the resistors, there is a jumper between the junction of R-1 and R-2 to point B which appears to short out R-2 & R-3.
What is the equivilant resistance of RAB equal to ??
Regards, Paul |
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Jim Smith
From:
Midlothian, TX, USA
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Posted 9 Aug 2002 5:47 pm
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| 150 ohms? |
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Paul Graupp
From:
Macon Ga USA
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Bill Terry
From:
Bastrop, TX
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Posted 9 Aug 2002 6:34 pm
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| Quote: |
| How long have you known this ?? |
I worked at Tandy Corp. in the mid-90's where I coded 4 and 8 bit microprocessors for answering machines, telephones, etc. In those days we used 7-segment LEDs or LCDs for most displays, and rather than a 7-seg display driver we typically used I/O from the chip and coded our own character set. We always had less pins than we wanted to do the display, key scan, etc. (since less GPI/O = cheaper processors), so I ended up spending a lot of time figuring how to 'light the right segments', make 9k of code fit in 8k ROM, not miss any interrupts, all that stuff.
Somewhere at sometime in that painful process this tidbit of trivia surfaced...
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Donny Hinson
From:
Glen Burnie, Md. U.S.A.
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Bob Lawrence
From:
Beaver Bank, Nova Scotia, Canada
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Posted 10 Aug 2002 4:19 am
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The answer is 300 ohms. Taking the path of least resistance current would flow from point A through the jumper located between
R2 and R3 (0 ohms) then through R3 (300 ohms)
to point B. It's still only 9 am what do I do for the rest of the day.
Bob
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Paul Graupp
From:
Macon Ga USA
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Posted 10 Aug 2002 7:11 am
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Bob; I'm afraid Donny saw through my smoke screen. Point A looks straight into R-1 and then via the lower jumper, gets to point B.
Via the upper jumper, point A at the junction of R-2 & R-3, looks to the left into R-2 and again throught the lower jumper to point B. To the right it sees R-3 and then directly to point B. So each time it sees a 300 ohm resistor and 300/3=100.
Donny; I must have been sleepy last night but maybe I rushed your riddle a bit. Give me a couple days to see if I can figure some easier solution out...... 
Regards, Paul |
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Joey Ace
From:
Hamilton, Ontario, Canada
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Posted 10 Aug 2002 7:48 am
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Don't you guys have anything better to do than discussing current events ?
Here's one I discovered in college, while laying on my back reading an Electronics Testbook:
Print DIODE on a paper, turn the paper over, so it's upside down and wrong side up.
Hold it to a light and you'll see the same word.
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Paul Graupp
From:
Macon Ga USA
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Marty Pollard
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Posted 10 Aug 2002 9:21 am
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2002
2112
2222
2552
2692
2882
2962
5005
5115
5555
etc. |
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Bob Lawrence
From:
Beaver Bank, Nova Scotia, Canada
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Posted 10 Aug 2002 5:40 pm
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Paul,
Thanks! I see where I went wrong. This time I had to draw it out. OK, I'm ready for another one.
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Donny Hinson
From:
Glen Burnie, Md. U.S.A.
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Posted 11 Aug 2002 8:56 am
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Closer, Paul, but no cigar! Actually, Marty is right on track, here. Yes, this (2002) is one of those upside-down years, and probably none of us will be around when it next happens...in 2112.  |
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Paul Graupp
From:
Macon Ga USA
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Andy Sandoval
From:
Bakersfield, California, USA
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Posted 4 Aug 2004 10:35 pm
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Hey can I have some of what you guys are smokin?...just kiddin. I read this thread just out of curiosity and just had to be a smart ass...
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loveridehd@aol.com
Carter D-10/C6 & E9, Oahu 6 string lap/C6, and two Resonators/open G
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John Daugherty
From:
Rolla, Missouri, USA
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Posted 5 Aug 2004 4:28 am
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Looks like you guys have been looking in the ID 10 T file.
Good Grief ........... |
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Jay Fagerlie
From:
Lotus, California, USA
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Posted 5 Aug 2004 6:02 am
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OK, here's one:
A man is on a boat with a pack of cigarettes and no matches, how did he manage to smoke?
Jay |
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Rick Alexander
From:
Florida, USA, R.I.P.
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Posted 5 Aug 2004 7:40 am
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He flicked his Bic . .  |
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Ray Minich
From:
Bradford, Pa. Frozen Tundra
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Posted 5 Aug 2004 10:26 am
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And here I was lookin' up Norton & Thevenin again...
Multiply 12345679 x 8 on yer calculator & see whatcha get.[This message was edited by Ray Minich on 05 August 2004 at 11:27 AM.] |
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jim milewski
From:
stowe, vermont
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Posted 6 Aug 2004 4:32 pm
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| did he borrow a light from someone else? |
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Jay Fagerlie
From:
Lotus, California, USA
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Posted 7 Aug 2004 9:02 am
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He threw a cigarette overboard and made the boat a "cigarette lighter"
HA!
I got that off an old Batman record I had when I was a kid.....
Jay |
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Paul Graupp
From:
Macon Ga USA
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Posted 7 Aug 2004 4:00 pm
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Ray; My little hand held Radio Shaq calculator only has eight digits but I see what you're saying. Sorta like the square root of 69, ehhh ??
Regards, Paul |
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